[Syphor]

In c, how do u print a specific amout of characters from a string. I always thought it was something like this:

Code:
 
char test[255] = "abcdefghijk"; 
 
printf("%s\n",test[3]);

Which return "d", so this way is correct. So whats wrong with the following code:

Code:
 
#include <stdio.h> 
 
int main() 
{ 
    FILE *fp; 
    char fileOutput[255]; 
    int     count; 
     
    fp = fopen( "data.dat", "rt" ); 
     
    while( !feof(fp) ) { 
        fgets( fileOutput, 255, fp ); 
        puts(fileOutput[2] ); 
    } 
     
    fclose(fp); 
 
 
    return 0; 
}

[BLAZE_MkIV]

The array indexing notation doesn't work like that.

Code:
char array[] = "abcdef"

*array == 'a'
*(array+1) == 'b'
array[2] == 'c'

Code:
printf("%s\n",test[3]);

results in just "d"

Your second piece of code results in just the third byte of the file.

Try snprintf or its equivalent.

[Syphor]

So how could I get a specific character out of fileOutput?

The reason i need this is because i have something similar in a function in a larger program i'm creating, and when this function reads the .dat file i want it to disregard all occurrences of "\n" and "/".

I wanted to do something like:

if (fileOutput[0]!="\n" || fileOutput[0]!="/") {
//do some stuff
} else {
//do some other stuff
}

[BLAZE_MkIV]

I din't realize you wanted a specific character. It read like you wanted to print the first n characters.

Code:
for ( i = 0; !feof(fp); ++i ) {
    array[ i ] = fgetc( fp );
}

fgetc gets one character at a time and moves the filepointer ahead one byte.