[jhs2n]

Hello all. I am running XCode 1.5 on a PowerBook G4. I need a very large array, as part of my research code. When I attempt to run the following stripped-down code

#include <iostream>
int main (int argc, char * const argv[]) {
double x[250000];
return 0;
}

I get an error from Xcode saying "Executable has exited due to signal 11 (SIGSEGV)," a segmentation fault I think. If I decrease the size of the array to 100,000, then the array can be declared and the program runs. What can I do to declare a larger array? Thanks.

[saddino]

Originally Posted by jhs2n

Hello all. I am running XCode 1.5 on a PowerBook G4. I need a very large array, as part of my research code. When I attempt to run the following stripped-down code

#include <iostream>
int main (int argc, char * const argv[]) {
double x[250000];
return 0;
}

I get an error from Xcode saying "Executable has exited due to signal 11 (SIGSEGV)," a segmentation fault I think. If I decrease the size of the array to 100,000, then the array can be declared and the program runs. What can I do to declare a larger array? Thanks.

You're blowing the stack; you should keep large arrays in the heap by allocating the memory dynamically:

Code:
double* x = (double*) malloc(250000 * sizeof(double));
if(x) {
    ...
    free(x); // when done
}

or

Code:
double* x = new double[250000];
if(x) {
    ...
    delete[] x; // when done
}

[jhs2n]

Thanks so much. The latter code did the trick.