[Glennfield]

I suspect that the answer is no, but I thought I'd ask anyway: I'm creating a class that has, as one of its instance variables, a 2-dimensional array of ints. I'd like the array to be differently sized in different instances of the class, if possible. Is there a way to do this without having to resort to the (far higher-level than I need) NSMutableArray class? I tried using a declaration like "int myArray[][];" in the header file, but that gave a compile-time error.

Any help is appreciated.

[smeger]

You could do something like the following:
</font><blockquote><font size="1" face="Geneva, Verdana, Arial, sans-serif">code:</font><hr /><pre style="font-size:x-small; font-family: monospace;">#include &lt;vector&gt;

class MyClass {
public:
MyClass (int arraySize)
{ _array.reserve(arraySize); };

protected:
vector&lt;int&gt; _array;
};</pre><hr /></blockquote><font size="1" face="Geneva, Verdana, Arial, sans-serif">To add an item to the back of the array, use _array.push_back(someInt). To get the number of elements, use _array.size(). Access the elements of your array using _array[someIndex].

Does this do the trick?

<small>[ 07-27-2002, 02:41 PM: Message edited by: smeger ]</small>

[Marshall]

It sounds like (from the mention of NSMutableArray) this is being done in Objective-C.

You could declare the variable in your header like this:

</font><blockquote><font size="1" face="Geneva, Verdana, Arial, sans-serif">code:</font><hr /><pre style="font-size:x-small; font-family: monospace;">@interface MyClass : NSObject
{
int **_theArray;
}
@end</pre><hr /></blockquote><font size="1" face="Geneva, Verdana, Arial, sans-serif">Then you would need to allocate the array and each column of it in your init: implementation, and free each column and the array itself in your dealloc: implementation.

[Edit: Bad keystroke posted it before I was finished]

<small>[ 07-27-2002, 04:47 PM: Message edited by: Marshall ]</small>