[kremmit]

Hi,

Can anyone figure out how the second part on each line gets created from the first part (the first part being the number)?
I have included 3 diff numbers to help you.


2316312 f3308c15c4
10104656 965c989dc5
10103242 0d6fa4a71c


Thanks!

[SafariX]

Originally posted by kremmit:
Hi,

Can anyone figure out how the second part on each line gets created from the first part (the first part being the number)?
I have included 3 diff numbers to help you.


2316312 f3308c15c4
10104656 965c989dc5
10103242 0d6fa4a71c


Thanks!

divide by and e^(#)

[Lancer409]

Genius' are avaliable at the genius bar of your local apple store. please inquire within...


that looks like ass! .. that's not a number as much as a flowing stream letters and numbers. it may be helpful to let us know what class this is for, and what he/she's been teaching lately.

[Mithras]

Do your homework.

[Xeo]

Well my first notion was that the second number is hexadecimal, but how it relates to the first number is unclear. It certainly isn't a simple representation of the first number as it's too long. They don't appear to divide each other. Perhaps they are relatively prime? I'm not sure.

[d4nth3m4n]

i would start by putting the hex in base 10 or the other way if you're feeling frisky.

from there though, you're on your own.

EDIT: could one be hex and the other base 8 (name for that? octary? lawl.)

[Xeo]

Originally posted by d4nth3m4n:
i would start by putting the hex in base 10 or the other way if you're feeling frisky.

from there though, you're on your own.

EDIT: could one be hex and the other base 8 (name for that? octary? lawl.)

Good call, or from his examples even base 7. I tried to see some relation between them but couldn't, no matter which base I assumed them to be.

More information on the problem would be helpful, I think.

[davidflas]

take the inverse of Pi and multiply by

[Spliffdaddy]

They appear to be similar to 64bit HEX based WEP encryption codes (wireless routers, etc). All the alphanumeric strings in the right-hand column are all 10 characters long - even though the numbers in the left-hand column vary in size between 7 & 8 digits.

[kremmit]

It's not a math problem in school - my buddy asked me if I could figure it out. I'm not sure what the numbers are. I don't know if he knows the answer, as is just testing me, or if he's stumped too.

[Sealobo]

let me increase the sample size so that people can get more clues...

2316312 f3308c15c4
10104656 965c989dc5
10103242 0d6fa4a71c
3654415 k465a654h
10125498 5464j454d
56465454 p565fds44
16551668 e44s44831
39485093 l4448477d

Go figure!

[alligator]

Can't be hex, the letters on the right are too large.

[C.A.T.S. CEO]

TRY THE MUSTARD MAN

[Ghoser777]

Originally posted by alligator:
Can't be hex, the letters on the right are too large.

Nevermind, I see the k now.

[Xeo]

Originally posted by Sealobo:
let me increase the sample size so that people can get more clues...

2316312 f3308c15c4
10104656 965c989dc5
10103242 0d6fa4a71c
3654415 k465a654h
10125498 5464j454d
56465454 p565fds44
16551668 e44s44831
39485093 l4448477d

Go figure!

So I take it you are the buddy?

I'm thoroughly stumped. The number of digits doesn't even seem to correspond:

7 10
8 10
8 10
7 9
8 9
8 9
8 9

The only things that are consistent are that the right one has more digits than the left, and the right one always has letters. It could be some even higher base (26??), but I'm starting to wonder. The left numbers do appear to be in base 10 as there are 9s.

[Cadaver]

Is this one of those classes where the instructor does a "proof by arm wave?"

"And as you can see here, this simply translates to the fifth derivative of the sum of the products to the nth root of e squared." Waves arm at chalkboard...

I had a few of those.

[Xeo]

Originally posted by Cadaver:
Is this one of those classes where the instructor does a "proof by arm wave?"

"And as you can see here, this simply translates to the fifth derivative of the sum of the products to the nth root of e squared." Waves arm at chalkboard...

I had a few of those.

My algorithms prof this semester would often say "and it's clear why this works..." or ask a probing question and when someone uses one word that sounds similar he'd yell out "RIGHT!!!!" and then erase what he had on the board saying "so we don't need to go through the proof, you all understand now."

Kinda a pain.

[Ghoser777]

When my professor got stuck / bored with a problem, he would say:

"And the rest I leave as an exercise for the student."

[itai195]

Originally posted by Xeo:
My algorithms prof this semester would often say "and it's clear why this works..." or ask a probing question and when someone uses one word that sounds similar he'd yell out "RIGHT!!!!" and then erase what he had on the board saying "so we don't need to go through the proof, you all understand now."

Kinda a pain.

I had a similar signals and systems professor in college. He'd also refer to various equations as 'this animal' or 'that animal.'

[spiky_dog]

Originally posted by Xeo:
My algorithms prof this semester would often say "and it's clear why this works..." or ask a probing question and when someone uses one word that sounds similar he'd yell out "RIGHT!!!!" and then erase what he had on the board saying "so we don't need to go through the proof, you all understand now."

Kinda a pain.

"clearly" and "trivially" are the two best math words ever

[alligator]

Could they be something totally different, like some weird way to annotate coordinates? Or maybe something like a public key for an encryption algorithm?

[skalie]

*bump*