[kent m]

Hi ho,

Is there a command for the osX terminal - bash - that will list sequentially numbered groups of file as one line instead of individually, while listing other files and directories correctly?

Meaning that a group of files:

image.001.tif
image.002.tif
image.003.tif
image.004.tif
image.005.tif

would be listed as

image.001-005.tif


and a dir with other files and dirs:

image.001.tif
image.002.tif
image.003.tif
image.004.tif
image.005.tif
dir01/
dir02/
imageB.tif

in it would be:

image.001-005.tif
dir01/
dir02/
imageB.tif

?

Wold love to have this...

Thanks,
KM

[Hal Itosis]

A command? Well, certainly no standard bash command (AFAIK).
But someone may have written such a script/tool. That's what it
would take I think. (And none too trivial either).

Well, the folder part would be easy. Not sure how to attack the
file-ranges portion. (You just need someone smarter than me!).

That shouldn't be too hard to find.
At any rate, it'll take some scripting.

[kent m]

Yeah, a company I used to work for had a cmd on linux that would do this - very very useful - and I hopefully can dig it up. I thought I'd try here though - never realized it would be so unique.

[larrinski]

maybe try The UNIX Forums - the Top UNIX & Linux Q&A on the Web which is the unix forum. Lots of unix geeks there!

[Hal Itosis]

Almost certainly it will be written in Perl
(which is about as legible as shorthand).

[kent m]

Thanks very much for the input. If I get ahold of something that isn't proprietary I'll post it back here. I had no idea that this would be such a hard thing to find!

best,
K

[jprice]

have you tried using sed and awk?

something like

ls ./*.tiff|sed 'y/./ /'|awk '{print $2}'

just put it in a variable get first output lastoutput and print string $1 .firstinput-lastoutput.tif