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Math puzzle...kinda
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Junior Member
Join Date: Dec 2002
Location: Denmark
Status:
Offline
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X=15
Y=13
X=Y+2
X(X-Y)=(Y+2)(X-Y)
X^2-XY=XY-Y^2+2X-2Y
X^2-XY-2X=XY-Y^2-2Y
X(X-Y-2)=Y(X-Y-2)
X=Y ->15=13
What went wrong
(N.B.: X^2 is X square)
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Indispensable MacOS X Software, music videos, music, science...
Please note: Speling erors are intentionel and are in play to sea if you pik up on them (i.e. the erors are their for a reason). So plaese, no mor emails regurding speling...an englihs is nod my mohter tongue. Tnhx!
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Registered User
Join Date: Jun 2004
Status:
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Mac Elite
Join Date: Jan 2003
Location: NYC
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i'm not really sure (summer vacation so my brain is effectively turned off) but (x - y - 2) = 0, so x(x - y - 2) = y(x - y - 2) is correct, since 0 = 0.
do i get a cookie? 
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Addicted to MacNN
Join Date: May 2001
Location: Cupertino, CA
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The problem is that you're dividing by 0
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Addicted to MacNN
Join Date: Oct 2001
Location: Yokohama, Japan
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The answer is X=Y=Err: Div by 0
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Professional Poster
Join Date: Jan 2003
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Whenever you divide an equality by a variable, you have to determine the domain of the new equality. In this case, the domain of the new equality is all X and Y such that X-Y-2 does not equal 0.
Thus, X = Y if and only if X does not equal Y + 2.
Unfortunately, X DOES equal Y + 2, so X can never equal Y.
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